How many times does the rate of reaction decrease when the temperature is decreased by a factor of 60 K.the temperature coefficient if reaction is 2.

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Solution

Dear Student,

The computation are expressed below,
$Q_{10} = (\frac{r a t e_{2}}{r a t e_{1}})^{\frac{10}{T_{2} - T_{1}}} = (\frac{r a t e_{2}}{r a t e_{1}})^{\frac{10}{60}} g i v e n \Rightarrow \frac{r a t e_{2}}{r a t e_{1}} = 2 \Rightarrow r a t e_{2} = 2 \times r a t e_{1} ∆ T = 2 \times 60 K r a t e_{2} = 2 \times 2 \times r a t e_{1} = 4 \times r a t e_{1} r a t e o f r e a c t i o n w i l l i n c r e a s e b y a f a c t o r o f 4 .$
Regards.

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