How many times more intense is a $90 d B$ sound than a $40 d B$ sound ?

2.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10^{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $10^{5}$
$90 = 10 l o g_{10} (\frac{I_{1}}{I_{0}})$
$\Rightarrow \frac{I_{1}}{I_{0}} = 10^{9}$ ......(i)
Again, $40 = 10 l o g_{10} (\frac{I_{2}}{I_{0}})$
$\Rightarrow \frac{I_{2}}{I_{0}} = 10^{4}$ ......(ii)
From Eqs.(i) and (ii), we get
$\frac{I_{1}}{I_{2}} = 10^{5}$

Suggest Corrections

Similar questions

90 d B

^{'} x^{'}

40 d B

x

90 dB

40 dB

80 d B

40 d B

L_{d B} = 10 {log}_{10} {\frac{I}{I}}_{o}

Join BYJU'S Learning Program