Question

How many triangles could be formed by taking 3 vertices of a hexagon?

• A. 45
• B. 30
• C. 20
• D. None of the above

Answer 1

The correct option is C

20

$RequiredWays{=}^6{C}_3=\frac{6!}{3!3!}=\frac{6\times 5\times 4\times 3!}{3!3\times 2\times 1}=\frac{6\times 5\times 4}{3\times 2\times 1}=20$