How many two-digit numbers are divisible by $8$ ?

12

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11

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10

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13

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Solution

The correct option is C $11$
Two digit number divisible by $8$ are
$16, 24, . . . . . . . . .96$
In this A.P
$a = 16, d = 8, a_{n} = 96$
$a_{n} = a + (n - 1) d$
$96 = 16 + (n - 1) 8$
$96 = 16 + 8 n - 8$
$8 n = 88$
$∴ n = 11$
Hence, $11$ number of two digit divisible by $8$ .

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