Question

How many types of gametes are found in F₁ progeny of cross AABBCC and aabbcc?

• A. 3
• B. 8
• C. 27
• D. 64

Answer 1

The correct option is B 8

Number of different types of gametes produced in an individual is $2^n$ where n is the number of heterozygous gene pair in an individual.
Here, the $F_1$ progeny of the cross would be AaBbCc. So, n = 3.
Therefore, types of gametes possible is $2^3=8$.

Types of gametes:

1. ABC
2. ABc
3. Abc
4. aBC
5. aBc
6. AbC
7. abC
8. abc