How many types of gametes will be produced by the genotype AaBbCcDDEE where all the genes are situated on different chromosomes?

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Solution

The correct option is A 8
No. of types of gametes $= 2^{n}$ ,
where n = no. of heterozygous gene pairs. There are 3 heterozygous gene pairs: Aa, Bb and Cc. So,
no. of types of gametes $= 2^{3} = 8$

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