Question

How many unique ways are there to arrange the letters of the word ${}^{\prime }PRIO{R}^{\prime }$

• A. $60$
• B. $120$
• C. $180$
• D. $150$

Answer 1

The correct option is A $60$

PRIOR

Number of letters $=5$

Out of which $R$ is repeated twice

$\Rightarrow$There are $4$ diffrent letters

Total number of arrangements

$=\frac{5!}{2}=\frac{120}{2}=60$

Therefore possible ways $=60$