How many unit cells are present in 39g of potassium that crystallizes in a BCC structure
I don't understand the method of solution???
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Solution
Atomic mass of potassium is 39 g.
In a BCC unit cell, there are 8 atoms at the corner of a cube and 1 atom at the centre.
Number of atom per unit cell =
8 x 1/8 + 1 x 1 = 2
Number of atoms in 39 g of potassium = 39/39 x 6.02 x 1023 [N is the Avogadro number = 6.02 x 1023] So, Number of unit cells in 39 g of potassium = 39/39 x 6.02 x 1023/2 = N/2 unit cells