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Question

How many unpaired e are present in [Ni(CN)4]2 ?

A
0
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B
2
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C
1
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D
3
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Solution

The correct option is A 0
Zero unpaired e are present in [Ni(CN)4]2. Ni is in +2 oxidation state. It has 3d8 electronic configuration.
It undergoes dsp2 hybridization to form 4 dsp2 hybrid orbitals which contain 8 electrons from 4 cyanide ligands. 8 electrons of Ni are present in four 3d orbitals. Thus, all electrons are paired. Due to this, [Ni(CN)4]2 is diamagnetic.

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