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Ionization Energies

How many unpa...

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How many unpaired electrons are present in the Brown Ring complex [Fe(H2O)5(NO)]SO4- (1) 4 (2) 3 (3) 0 (4) 5

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Similar questions

Q. How many unpaired electrons are present in the Brown Ring complex

[F e (H_{2} O)_{5} (N O)] S O_{4}

?

Q. How many electrons are present in

t_{2 g}

d - o r b i t a l s

of central metal cation in

[F e (H_{2} O)_{5} (N O)] S O_{4}

brown ring complex?

Q. In the formula of brown ring complex

[F e {(H_{2} O)}_{5} (N O)] S O_{4}

, the magnetic moment is 3.87 B.M. The oxidation state of Fe and number of unpaired electrons present respectively are :

Q. The number of unpaired electrons present in the species

[F e (H_{2} O)_{5} N O]^{2 +}

which is formed during 'brown ring' test is

Q. The brown ring complex is formulated as

[{F e (H_{2} O)}_{5} N O] {S O}_{4}

. The oxidation state of iron is:
(A) +1 (B) +2 (C) +3 (D) 0

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