Question

How many water molecules are produced in the complete neutralization of one mole phosphoric acid potassium hydroxide?

Answer 1

Equation : $3KOH+H_{3}P{O}_4\to K_{3}P{O}_4+3H_{2}O$

Ratio of $KOH:H_{3}P{O}_4=3:1$ & $H_{3}P{O}_4:H_{2}O=1:3$

$3$ moles of water are obtained for $1$ mole of complete neutralization of $H_{3}P{O}_4$.

Sol $1$ mol $\left(H_{3}P{O}_4\right)=\frac{3molof{H}_{2}O}{1molof{H}_{3}P{O}_4}\times \frac{6.022\times {10}^{23}molecules}{1mol}$$=1.81\times {10}^{24}{H}_{2}O$ molecules.