The correct option is D 25
A Stirling number of the second kind, denoted as S(n, r), is the number of ways a set of n elements can be partitioned into r non-empty sets.
The goal is to find S(5, 3). From the recurrence relation,
S(5,3) = 3S(4,3) + S(4,2)
The values of S(4,3), S(4,2) can be drawn from the basic cases. S(4,3)=4C2=6 and S(4,2)=24−1−1=7.
Thus, S(5,3) = 3 ∗ 6 + 7 = 25.