how many ways can 1000 be written as sum of 2 or more consecutive natural numbers?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 3
option (c)

Shortcut:- Number of ways of writing a number as a sum of 2 consecutive natural numbers= number of odd factors of that number-1

$1000 = 2^{3} \times 5^{3}$ . number of odd factors = 4

Answer =4-1=3

Suggest Corrections

Similar questions

In how many ways can the number $(9!)^{2}$ be written as a sum of two or more consecutive positive integers?

In how many ways can the number 286 be written as a sum of two or more consecutive integers?

Join BYJU'S Learning Program