Question

How many ways can $4$ prizes be given away to $3$ boys, if each boy is eligible for all the prizes?

• A. $256$
• B. $24$
• C. $12$
• D. $81$

Answer 1

The correct option is D $81$

There are $4$ prizes to be given to $3$ boys.

The first prize can be given to any of the $3$ boys $={}^3{C}_1=3$ ways.

Similarly the other $3$ prizes cab be given to any of the $3$ boys.

Total no. of permutations $=3\times 3\times 3\times 3=3^4=81$

Hence, the answer is $81.$