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Question
How many ways can 5girls and 3boys be seated in a row so that no two boys are together
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Solution
14400 ways.
5 girls can sit in 5!= 120ways and boys has to sit between them so in 6 place they can sit in 6c3=20 ways and 3 can be combine themself in 3!ways..
so total will be 120*20*6=14400 ways.
5 girls can sit in 5!= 120ways and boys has to sit between them so in 6 place they can sit in 6c3=20 ways and 3 can be combine themself in 3!ways..
so total will be 120*20*6=14400 ways.
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