1
Question
How many ways can 5girls and 3boys be seated in a row so that no two boys are together
Open in App
Solution
14400 ways.
5 girls can sit in 5!= 120ways and boys has to sit between them so in 6 place they can sit in 6c3=20 ways and 3 can be combine themself in 3!ways..
so total will be 120*20*6=14400 ways.
5 girls can sit in 5!= 120ways and boys has to sit between them so in 6 place they can sit in 6c3=20 ways and 3 can be combine themself in 3!ways..
so total will be 120*20*6=14400 ways.
Suggest Corrections
3
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
