How many words can be formed by rearranging the letters of the word $^{'} A S C E N T^{'}$ such that $A$ and $T$ occupy first and last positions respectively?

5!

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4!

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6! - 2!

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\frac{6!}{2!}

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Solution

The correct option is B $4!$
ASCENT
A $⟶$ First letter
T $⟶$ Last letter
Number of ways of arranging $= 4!$ ways
Therefore Number of ways $= 4!$

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How many words can be formed by rearranging the letters of the word ′ASCENT′ such that A and T occupy first and last positions respectively?

The correct option is B 4!ASCENT A⟶ First letter T⟶ Last letter Number of ways of arranging =4!ways Therefore Number of ways =4!

How many words can be formed by rearranging the letters of the word $^{'} A S C E N T^{'}$ such that $A$ and $T$ occupy first and last positions respectively?

The correct option is B $4!$
ASCENT
A $⟶$ First letter
T $⟶$ Last letter
Number of ways of arranging $= 4!$ ways
Therefore Number of ways $= 4!$