How many words can be formed with the letters of FAILURE when all the vowels should come together?

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Solution

(FAILURE)
(a i v e)(f)(l)(r)
$\Rightarrow 4! \times 4! = 24 \times 24 = 576$ ways

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How many words can be formed with the letters of FAILURE when all the vowels should come together?

(FAILURE)(a i v e)(f)(l)(r)⇒4!×4!=24×24=576 ways

(FAILURE)
(a i v e)(f)(l)(r)
$\Rightarrow 4! \times 4! = 24 \times 24 = 576$ ways