Question

How many words can be formed with the letters of the word ${}^{\prime }CHAI{R}^{\prime }$ such that $A$ is always before $I$

• A. $120$
• B. $180$
• C. $60$
• D. $90$

Answer 1

The correct option is C $60$

Number of letters in the given word $=5$
Number of words formed with $A$ before $I=$Number of words with $I$ before $A$
Total number of words formed $=5!=120$
$\therefore$ Required number of words $=\frac{120}{2}=60$