Question

How many words can be formed with the letters of the word MATHEMATICS by rearranging them

• A. $\frac{11!}{2!2!}$
• B. $\frac{11!}{2!}$
• C. $\frac{11!}{2!2!2!}$
• D. $11!$

Answer 1

The correct option is C $\frac{11!}{2!2!2!}$

Since there are 2 M's, 2 A's and 2T's.
$\therefore$ Required number of ways are $\frac{11!}{2!2!2!}$