How many words can be formed with the letters of the word $^{'} O M E G A^{'}$ when vowels occupy only odd places?

12

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24

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18

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36

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Solution

The correct option is A $12$
O _ E _ A
Here $2$ letters can be arranged in $2!$
These vowels can be arranged themselves in $31 = 3$
Total $3! \times 2! = 12$

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