Question

How many zeroes are there in $1\times 2\times 3\times 4...........49\times 50$:

• A. $10$
• B. $11$
• C. $12$
• D. $13$

Answer 1

Answer: (C)

$12$

The given product can be written as $50!$

So, to find number of zeros in $50!$, we must divide $50$ by the powers of $5$ as following-

No. of zeros $=\frac{50}{5}+\frac{50}{5^2}+......+\frac{50}{5^n}$

No. of zeros $=10+2$ $[Consideringremainder\ge 1]$

No. of zeros $=12.$

This is the required answer.