How many zeroes do the polynomials
P1(x)=x3+x2+x+1 and
P2(x)=x2+1
have in common?
1
P1(x)=x3+x2+x+1=(x+1)(x2+1).
So, There are two factors of P1(x)
P2(x)=x2+1
So, x2+1 is common in both
Lets find zeroes of x2+1, x2+1=0⇒x2=−1
x=√−1=i Where i is iota.
∴ Only one zero (i.e. x = i) is common to both polynomials