Question

How may acute angles are there in a regular pentagon?

• A. $2$
• B. $0$
• C. $3$
• D. $4$

Answer 1

Answer: (B)

$0$

$\Rightarrow$ Given figure ABCDE is a regular pentagon.

$\Rightarrow$ We know that pentagon contains 5 sides, so $n=5$.

$\Rightarrow$ Sum of interior angles in pentagon = $(n-2)\times {180}^{\circ }$

$\Rightarrow$ $(5-2)\times {180}^{\circ }$

$\therefore$ Sum of interior angles in pentagon = ${540}^{\circ }$

$\Rightarrow$ Each angle in pentagon = $\frac{{540}^{\circ }}{5}$

$\therefore$ Each angle in pentagon = ${108}^{\circ }$

We know that ${108}^{\circ }$ is an obtuse angle.

Hence, we get there is $0$ acute angle in regular pentagon.