The correct option is C 7. 6C4.8C4
Total letters = 11, No of S's = 4
First place 7 letters at lot place other than S = 7!4!2!
Now place S at X places such that no two S are adjacent
= 8P44!=8C4
Hence, total number of arrangments
= 7!4!2! X 8C4 = 7. 6C4 X 8C4