Question

how mosphany molecules and atoms of phosphorous are present in 0.1 moles white phorous?

Answer 1

$$\begin{gathered} \text{Dear Student,} \\ \mathrm{Number}\mathrm{of}\mathrm{molecules}\mathrm{of}\mathrm{phosphorous}\mathrm{in}1\mathrm{mole}=6.022\times {10}^{23}\mathrm{molecules}. \\ \mathrm{Number}\mathrm{of}\mathrm{molecules}\mathrm{of}\mathrm{phosphorous}\mathrm{in}0.1\mathrm{mole}=\frac{6.022\times {10}^{23}}{1}\times 0.1\mathrm{molecules}=6.022\times {10}^{22}\mathrm{molecules}. \\ 1\mathrm{molecule}\mathrm{of}\mathrm{phosphorous}\mathrm{contain}=4\mathrm{atoms}\mathrm{of}\mathrm{phosphorous} \\ \mathrm{o}.1\mathrm{mole}\mathrm{of}\mathrm{phosphorous}\mathrm{contain}=4\times 6.022\times {10}^{22}\mathrm{atoms}\mathrm{of}\mathrm{phosphorous}=2.4088\times \times {10}^{23}\mathrm{atoms}\mathrm{of}\mathrm{phosphorous} \end{gathered}$$