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Standard XII
Chemistry
Stoichiometric Calculations
How much amou...
Question
How much amount of
C
u
S
O
4
⋅
5
H
2
O
is required for liberation of
2.54
g
of
I
2
when titrated with
K
I
?
A
2.5
g
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B
4.99
g
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C
2.4
g
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D
1.2
g
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Solution
The correct option is
C
4.99
g
2
C
u
S
O
4
⋅
5
H
2
O
+
4
K
I
→
C
u
2
I
2
+
2
K
2
S
O
4
+
I
2
254
g
+
10
H
2
O
Molecular weight of
2
C
u
S
O
4
⋅
5
H
2
O
=
[
2
(
63.5
+
32
+
64
)
+
10
(
18
)
]
g
=
499
g
254
g
of
I
2
is liberated by
499
g
C
u
S
O
4
⋅
5
H
2
O
.
2.54
g
of
I
2
will be liberated by
x
g
C
u
S
O
4
⋅
5
H
2
O
.
x
=
499
×
2.54
254
=
4.99
g
Hence, the correct option is
B
Suggest Corrections
0
Similar questions
Q.
How much amount of
C
u
S
O
4
.
5
H
2
O
required for liberation of
2.54
g
I
2
when titrated with
K
I
?
Q.
How much amount of
C
u
S
O
4
.5
H
2
O
required for liberation of
2.54
g
I
2
when titrated with
K
I
?
Q.
638.0
g of
C
u
S
O
4
solution is titrated with excess of
0.2
M
K
I
solution. The liberated
I
2
required
400
mL of
1.0
M
N
a
2
S
2
O
3
for complete reaction. The percentage purity of
C
u
S
O
4
in the sample is:
Q.
2.5
g sample of copper is dissolved in excess of
H
2
S
O
4
to prepare
100
ml of
0.02
M
C
u
S
O
4
(
a
q
)
.
10
ml of
0.02
M
solution of
C
u
S
O
4
(
a
q
)
is mixed with excess of
K
I
to show the following changes:
C
u
S
O
4
+
2
K
I
⟶
K
2
S
O
4
+
C
u
I
2
2
C
u
I
2
⟶
C
u
2
I
2
+
I
2
The liberated iodine is titrated with hypo (
N
a
2
S
2
O
3
) which requires
V
ml of
0.1
M
hypo solution for its complete reduction.
The amount of
I
2
liberated in the reaction of
10
ml of
0.02
M
solution with excess
K
I
is
:
Q.
3 gm of
C
u
S
O
4
,
5
H
2
O
sample containing inert impurity reacted with KI and the liberated
I
2
reacted with
10
m
l
of
0.5
M
N
a
2
S
2
O
3
. The % purity of
C
u
S
O
4
.5
H
2
O
will be:
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