How much amount of NaCl should be added to 600 g of water ( Density = 1.00g/ml) to decrease the freezing point of water to “-0.2°C” ? ( The freezing point depression constant for water =2 K Kg mol-1)
Solution:
∆Tf=0·2°C∆Tf=i×kf×mNaCl→Na++Cl-i=20.2=2×2×w58.5×1000600=1.2×58.540=1.76gm