Question

How much amount of $N{H}_3$ is produced when 28 g of nitrogen react with 6 g of hydrogen?

• A. 34

Answer 1

The correct option is A 34
According to the law of conservation of mass, the total mass of the products is equal to that of reactants, in a chemical reaction.

$\text{3}{H}_2\left(g\right)+{\text{N}}_2$(g) → $\text{2}{NH}_3\left(g\right)$
6 g 28 g X g

The mass of $N{H}_3$ produced is equal to the sum of mass of hydrogen and nitrogen that reacted to give $N{H}_3$.

Hence, the mass of $N{H}_3$ = X g = 28 + 6 = 34 g.