How much calcium oxide is formed when $82 g$ of calcium nitrate is heated?
Also, find the volume of nitrogen dioxide evolved :
$2 Ca {({NO}_{3})}_{2} ⟶ 2 CaO + 4 {NO}_{2} + O_{2}$
$(Ca = 40, N = 14, O = 16)$

Open in App

Solution

Step 1. Calculate the molar mass :
$2 Ca {({NO}_{3})}_{2} (aq) ⟶ 2 CaO (aq) + 4 {NO}_{2} (g) + O_{2} (g)$
$2 [40 + 2 (14 + 48)] \to 2 (40 + 16) 4 V o l .$
$328 g$ $\to 112 g$
Step 2. Calculate the volume of nitrogen dioxide evolved :
328 g will decompose to form $112 g$ of $CaO$
$1 g$ will decompose to form $\frac{112}{328} g$ of $CaO$
$82 g$ will decompose to form $\frac{112}{328} \times 82 g$ $= 28 g$ of $CaO$
$328 g$ will decompose to form 4 vol of ${NO}_{2}$
$328 g$ will decompose to form $4 \times 22.4 L$ of ${NO}_{2}$
$1 g$ will decompose to form $\frac{4 \times 22.4}{328} L$ of ${NO}_{2}$ .
$82 g$ will decompose to form $= \frac{4 \times 22.4}{328} \times 82 = 22.4 L$ of ${NO}_{2}$
=1 Volume of ${NO}_{2} .$

Suggest Corrections

Similar questions

32 g m s

20

82 g

2 C a {(N O_{3})}_{2} ⟶ 2 C a O + 4 N O_{2} + O_{2}

(C a = 40, N = 14, O = 16)

350 g

C a = 40 u

(A t o m i c m a s s o f C a = 40 u, O = 16 u)

%

C a = 40, O = 16, S = 32, N = 14

Join BYJU'S Learning Program