How much calcium oxide will be formed on decomposition of 350g of limestone.
(Given: Atomic mass of Ca=40u)
A
224g
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B
220g
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C
196g
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D
320g
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Solution
The correct option is C196g We know that,CaCO3heat−−→CaO+CO2(g)
Molar mass of limestone, CaCO3=40+12+48=100g/mol
Molar mass of lime, CaO=40+16=56g/mol ∵100gCaCO3produces56gCaO ∴350gCaCO3produces56×350100=196gCaO