How much canvas is required to make a tent of base area $440$ sq metres and height $12$ metres?

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Solution

Base area $= π r^{2}$
$∴ π r^{2} = 440$
$∴ r^{2} = 440 \times \frac{7}{22}$
$= 140$
Required canvas $= π . r . l$
$= π r . \sqrt{r^{2} + h^{2}}$
$= \frac{22}{7} \times \sqrt{140} . \sqrt{140 + 144}$
$= \frac{22}{7} \times 11.83 \times 16.85$
$= 626.48$ metre (approx).

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The circumference of the base of a $10 m$ high conical tent is $44 m e t r e s .$ Calculate the length of canvas used in making the tent if width of canvas is $2 m .$ (Use $π = \frac{22}{7}$ ).

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How much canvas is required to make a tent of base area 440 sq metres and height 12 metres?

Base area =πr2∴πr2=440∴r2=440×722=140Required canvas =π.r.l=πr.√r2+h2=227×√140.√140+144=227×11.83×16.85=626.48 metre (approx).

How much canvas is required to make a tent of base area $440$ sq metres and height $12$ metres?

Base area $= π r^{2}$
$∴ π r^{2} = 440$
$∴ r^{2} = 440 \times \frac{7}{22}$
$= 140$
Required canvas $= π . r . l$
$= π r . \sqrt{r^{2} + h^{2}}$
$= \frac{22}{7} \times \sqrt{140} . \sqrt{140 + 144}$
$= \frac{22}{7} \times 11.83 \times 16.85$
$= 626.48$ metre (approx).