Question

How much charge in Faraday is required for the reduction of $1$ mole of $A{g}^{+}$ to Ag?

• A. $19.29\times {10}^{4}C$
• B. $96487C$
• C. $38.59\times {10}^{4}C$
• D. $4824C$

Answer 1

Answer: (B)

$96487C$

According to the problem:

Let the formula required charge $n\times F$

$n=$ difference of charge on ions

$F$ is constant $=96487C$

Here $n=1$

Hence required charge$=1\times 96487C$

$=96487C$.