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Question

How much charge is required for the following reductions:

(i) 1 mol of Al3+ to Al.

(ii) 1 mol of Cu2+ to Cu.

(iii) 1 mol of to Mn2+.

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Solution

(i)

Required charge = 3 F

= 3 × 96487 C

= 289461 C

(ii)

Required charge = 2 F

= 2 × 96487 C

= 192974 C

(iii)

i.e.,

Required charge = 5 F

= 5 × 96487 C

= 482435 C


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