Question

How much clay is dug out in digging a well measuring 3 m by 2 m by 5 m?

Answer 1

$$\begin{gathered} \mathrm{The}\mathrm{measure}\mathrm{of}\mathrm{well}\mathrm{is}3\mathrm{m}\times 2\mathrm{m}\times 5\mathrm{m}. \\ \therefore \mathrm{Volume}\mathrm{of}\mathrm{the}\mathrm{clay}\mathrm{dug}\mathrm{out}=(3\times 2\times 5){\mathrm{m}}^3=30{\mathrm{m}}^3 \end{gathered}$$