Question

How much current is required to obtain half mole $Ni$ from electrolysis of $NiS{O}_4$ solution?

• A. $2F$
• B. $1F$
• C. $0.5F$
• D. $4F$

Answer 1

Answer: (B)

$1F$

By Faraday's law, $w=Zq$.

$w=\frac{E}{96500}\times q$ [$q$ in coulomb]

Where $E=$ equivalent weight $=\frac{M}{2}$ in this case.

$\therefore \frac{w}{M}=\frac{1}{2}\times Q$ [where $Q$ is in farads].

$\because \frac{w}{M}=\frac{1}{2}⟹Q=1F$