Question

How much current will an electric bulb draw from a $220V$ source, if the resistance of the filament of the bulb is $1100\Omega$?

Answer 1

Step 1- Given data and formula

1. Potential difference $V=220V$
2. Resistance $R=1100\Omega$

Consider the electric current drawn from the source is $I$.

From Ohm's law, the formula for $I$ is

$I=\frac{V}{R}$

Step 2- Finding the electric current

Substituting the known values,

$$\begin{gathered} I=\frac{V}{R} \\ I=\frac{220V}{1100\Omega } \\ I=0.2A \end{gathered}$$

Hence, the electric current drawn from the source is $0.2A$.