Question

How much current will an electric bulb draw from a $220V$source, if the resistance of the bulb filament is $1200\Omega$?

Answer 1

Step 1: Given data:

Potential difference, $v_p=220V$

Resistance of the bulb filament, $R=1200\Omega$

Current drawn by the bulb, $I=?$

Step 2: Formula used:

According to Ohm's law,

$I=\frac{v_p}{R}$ …………………….(1)

Step 3: Calculation of the current drawn by the bulb:

Substituting the given values in equation (1), we get

$$\begin{gathered} I=\frac{220V}{1200\Omega } \\ I=0.18A \end{gathered}$$

Hence, the electric current drawn by the bulb is equal to $0.18A$.