Question

How much distance an electron revolving in $3^{rd}$ orbit of $H{e}^{+}$ ion will travel in one second.

• A. $1.458\times {10}^6$ m
• B. $3.28\times {10}^6$ m
• C. $4.862\times {10}^5$ m
• D. $2.917\times {10}^6$m

Answer 1

The correct option is A $1.458\times {10}^6$ m

$v_n=v_0\times z/n$ m/s

$v_0=2.188\times {10}^6$

n = 3

z = 2

substituting the above values

$v_n=2.188\times {10}^6\times 2/3$

$v_n=1.458\times {10}^6$ m/s