Question

How much does the area of a square reduce with respect to its original area when the length of its side is halved?

Answer 1

Let the square of side 's' be 'A'.
This implies that $s^2=A$
Now when the length is halved, i.e., it becomes $\frac{s}{2}$, then the new area is $\frac{s}{2}$× $\frac{s}{2}$= $\frac{s^2}{4}$ = $\frac{A}{4}$
Thus, the area of the square reduces to one-fourth of its original area.