Question

how much energy is gained by an electron accelerated through a potential difference of 3.0x10^2

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{The}\mathrm{energy}\mathrm{gained}\mathrm{is}\mathrm{equal}\mathrm{to}\mathrm{the}\mathrm{work}\mathrm{done}\mathrm{on}\mathrm{the}\mathrm{electron}\mathrm{by}\mathrm{the}\mathrm{electric}\mathrm{field}. \\ \mathrm{The}\mathrm{potential}\mathrm{difference}\mathrm{must}\mathrm{be}\mathrm{positive}\mathrm{for}\mathrm{the}\mathrm{electron}\mathrm{to}\mathrm{gain}\mathrm{potential}\mathrm{energy}. \\ \mathrm{V}=-\frac{\mathrm{W}}{\mathrm{q}} \\ \mathrm{W}=-\mathrm{qV} \\ \mathrm{W}=-\left(-1.6\times {10}^{-19}\right)\times 3.0\times {10}^2 \\ \mathrm{W}=4.8\times {10}^{-17}\mathrm{J} \end{gathered}$$