How much energy is needed to raise the temperature of 5 g of ice from -20- C to 35- C - S ice -0-5 cal - g - L f -80 cal - g - S water -1 cal - g A- 625 calB- 750 calC- 175 calD- 675 cal

The correct option is A 625 calQ = mS_iceΔ T + mL_f + m S_waterΔ T = 5 ×1/2× 20 + 5 × 80 + 5 × 1 × 35 nbsp; nbsp; = 50 + 400 + 175 nbsp; nbs ...

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How much ener...

Question

How much energy is needed to raise the temperature of $5 g$ of ice from
$- 20^{o} C t o 35^{o} C$ ?
$(S_{i c e} = 0.5 c a l / g, L_{f} = 80 c a l / g, S_{w a t e r} = 1 c a l / g)$

625 c a l

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750 c a l

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175 c a l

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675 c a l

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Similar questions

100 g

Δ H_{v} = 540 c a l / g

Δ H_{f} = 80 c a l / g

C_{w a t e r} = 1 c a l / g^{o} C

100 g

263 K

283 K

C_{i c e} = 0.49 c a l / (g^{o} C)

C_{w a t e r} = 1.00 c a l / (g^{o} C)

Δ H_{f u s} = 79.8 c a l / g

Δ H_{v a p} = 540 c a l / g

0.05 k g

373 K

0.45 k g

253 K

L_{f u s i o n} = 80 c a l / g = 336 J / g

L_{v a p o r i s a t i o n} = 540 c a l / g = 2268 J / g

S_{i c e} = 2100 J / k g K = 0.5 c a l / g K

S_{w a t e r} = 4200 J / k g K = 1 c a l / g K

1^{\circ} C

120 c a l .

100^{o} C

(L_{s t e a m} = 540 c a l / g, L_{i c e} = 80 c a l / g; S_{w a t e r} = 1 c a l / g^{o} C)

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