How much energy is released when a $_{8} O^{16}$ nucleus is completely converted into energy?
The binding energy per nucleon of $_{8} O^{16}$ is $7.97 M e V$ and $m_{p} = 1.0078 u$ and $m_{n} = 1.0087 u$

14899.438 M e V

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148.99 M e V

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4489.73 M e V

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448.973 M e V

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Solution

The correct option is A $14899.438 M e V$
Binding Energy $= E = △ m c^{2}$
$△ m =$ mass of nucleus $-$ (mass of proton + neutron)
Multiplying both sides by $c^{2}$
$△ m c^{2} =$ (mass of nucleus) $c^{2} -$ (mass of proton + neutron) $c^{2}$
$= 7.97 \times 16 - 8 (1.0078 + 1.0087) 931 E = 127.52 - 15018.892 E = - 14899.438 M e V$

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