Question

How much energy transferred when $1$ gram of boiling water at ${100}^{o}C$ turns to water at $0^{o}C$?.

Answer 1

Mass of water (m) = 1g

Initial temperature $\left(T_1\right)=0^{0}C$

Final temperature $\left(T_2\right)={100}^{0}C$

Specific heat of water (s) = 1cal / g-c

Heat energy transferred $Q=m_s(T_2-T_1)$

$Q=1\times 1\times (100-0)$

$=100$ cal

100 cal is the energy transferred