How much g of $H_{2} O$ is formed?

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Solution

Given a balanced equation: $2 H_{2} + O_{2} ⟶ 2 H_{2} O$ .
It is clear that $1$ mole of oxygen requires $2$ moles of hydrogen i.e. $4$ g of hydrogen.
Here, we have one mole of oxygen and only $1$ gram of hydrogen, hence hydrogen is limiting reagent.
$4$ grams of hydrogen gives $36$ grams of water.
Hence, $1$ gram of hydrogen gives $9$ grams of water.

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