How much gas (in litres ) will be produced at $0^{\circ} C$ and $760 m m$ of pressure when $10 g$ of oxalic acid was heated with concentrated sulphuric acid ?

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Solution

$(C O O H)_{2} H_{2} S O_{4} \to C O + C O_{2} + H_{2} O$

$10 g = \frac{10}{90}$ moles
moles of $C O$ produced $= \frac{10}{90} \frac{1}{9} \Rightarrow$ mole of $C O_{2}$ produced $= \frac{10}{90} = \frac{1}{9}$
$∴$ Volume of gases produced at $0^{\circ} C$ & $760 m m$ of $H g$ ( at NTP )
$(\frac{1}{9} + \frac{1}{9}) = \frac{2}{9} \times 22.4 l i t = 4.96 l i t$

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How much gas (in litres ) will be produced at 0∘C and 760mm of pressure when 10g of oxalic acid was heated with concentrated sulphuric acid ?

(COOH)2H2SO4→CO+CO2+H2O10g=1090 moles moles of CO produced =109019⇒ mole of CO2 produced =1090=19 ∴ Volume of gases produced at 0∘C & 760mm of Hg ( at NTP ) (19+19)=29×22.4lit=4.96lit

How much gas (in litres ) will be produced at $0^{\circ} C$ and $760 m m$ of pressure when $10 g$ of oxalic acid was heated with concentrated sulphuric acid ?