How much heat energy is gained when 5 kg of water at 20- C is brought to its boiling point-Specific heat of water - 4-2 kJ kg-1 c-1

Given: Mass of water, m = 5 kg Specific heat of water, nbsp;c = 4.2 kJ kg^ 1 ^∘C^ 1 Rise in temperature of water Δθ = 100 20 = 80^∘ C Heat gained is given b ...

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Byju's Answer

Standard XI

Physics

Calorimetry

How much heat...

Question

How much heat energy is gained when $5 k g$ of water at $20^{\circ} C$ is brought to its boiling point?
$(Specific heat of water = 4.2 k J k g^{- 1} c^{- 1})$

$1680 k J$

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$1700 k J$

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$1720 k J$

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$1740 k J$

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Solution

The correct option is A
$1680 k J$

Given:
Mass of water, $m = 5 k g$
Specific heat of water, $c = 4.2 k J k g^{- 1}^{\circ} C^{- 1}$
Rise in temperature of water $Δ θ = 100 - 20 = 80^{\circ} C$

Heat gained is given by:
$Q = m c Δ θ$
$Q = 5 \times 4.2 \times 10^{3} \times 80 J$
$Q = 1680 \times 10^{3} J = 1680 k J$

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Similar questions

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How much heat energy is gained when 5 kg of water at 20∘C is brought to its boiling point? (Specific heat of water=4.2 kJ kg−1c−1)

The correct option is A 1680 kJ Given: Mass of water, m=5 kg Specific heat of water, c=4.2 kJ kg−1 ∘C−1 Rise in temperature of water Δθ=100−20=80∘C Heat gained is given by: Q=mcΔθ Q=5×4.2×103×80 J Q=1680×103J=1680 kJ

How much heat energy is gained when $5 k g$ of water at $20^{\circ} C$ is brought to its boiling point?
$(Specific heat of water = 4.2 k J k g^{- 1} c^{- 1})$