The correct option is C 4200 kJ
We know that,
Freezing point of water is 0∘ C
∴ Change in temperature, ΔT=0∘ C−100∘ C=−100∘ C
Also,
Q=mcΔT
Where, c is specific capacity of water
Given: c=1 cal/g∘C=1 kcal/kg∘C
=4200 J/kg∘C
∴Q=mcΔT=10×4200×(−100)
=−42×105 J
=−4200 kJ
where (-ve) sign indicates that heat is released on cooling.
∴ Heat released =4200 kJ