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Question

How much heat is required to convert 10g of ice at −5oC into steam at 100oC

A
5151cal
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B
4672cal
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C
7226cal
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D
6000cal
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Solution

The correct option is B 7226cal
Given : How much heat is required to convert 10g10g of ice at 5oC into steam at 100oC
m=10g
Specific heat of ice=0.5
Latent heat of fusion from ice to water L=80cal
Specific heat of water=1
Latent heat of vaporization L=540cal
Solution :
Case 1
Heat required to convert ice at 5oC to 0oC
Q1=mSΔT Q1=10×0.5×5 Q1=25cal
Case 2
Heat required to convert ice into water at 0oC
Q2=mL Q2=10×80
Q2=800cal
Case 3
Heat required to convert water from 0oCto100oC
Q3=mSΔT Q3=10×1×100
Q3=1000cal
Case 4
Heat required to convert water into steam at 100oC
Q4=mL Q4=10×540
Q4=5400cal

Total heat required Qtotal=Q1+Q2+Q3+Q4
Qtotal=25+800+1000+5400
Qtotal=7225cal


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