Question

How much heat is required to raise the temperature of $100g$ of water from $5^{\circ }C$ to ${95}^{\circ }C$?

• A. $900kcal$
• B. $90kcal$
• C. $10kcal$
• D. $9kcal$

Answer 1

The correct option is D $9kcal$

Given , $m=100g,{\theta }_1=5^{0}C,{\theta }_2={95}^{0}C$

We have , specific heat of water $c=1cal/g{-}^{o}C$

Now , heat required to raise the temperature of water is given by ,

$Q=mc\Delta \theta =mc({\theta }_2-{\theta }_1)$

or $Q=100\times 1\times (95-5)=9000cal=9kcal$